70v^2=-32v

Solution for 70v^2=-32v equation:

70v^2=-32v

We move all terms to the left:

70v^2-(-32v)=0

We get rid of parentheses

70v^2+32v=0

a = 70; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·70·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*70}=\frac{-64}{140}
=-16/35
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*70}=\frac{0}{140}
=0
$